We have two ways to find the currents delivered by the voltage sources – i
1
and
i
2
. In the first method, we find the voltage across M and N in the circuit in Fig. 10.5-11(a)
as v
MN
8i 0.018 di/dt and then find i
2
as (7 – v
MN
)/6 and i
1
as (v
MN
14)/12.
In the second method, we realise that all variables in this circuit will have a
Ae
–t/
τ
term and a steady-state term, and that we can find the arbitrary constant Aif we
know the value of the particular variable at 0
+
. So, we set out to find the initial and final
(i.e., steady-state) value of the source currents. The inductor current was at 0.5 A at
t 0
+
. The voltage ...
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