The circuit in Fig. 8.6-11 shows a 50 Hz, 230 V rms AC voltage source delivering power to
a 10 Ω//j20 Ω inductive load through a feeder line of series impedance 0.4 j1 Ω. (i) Find
the current phasor delivered by the source, load voltage phasor, average power deliv-
ered to the load and the efficiency of power delivery if the capacitor C is discon-
nected. (ii) Repeat part (i) with X
C
–20 Ω .
SOLUTION
(i)We use voltage division principle to determine the load voltage first. The parallel
combination of 10 Ω and j20 Ω is in series with 0.4 j1 Ω. Therefore, the voltage across
the load, V
L
is obtained as
Now, ...
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