
A frequency is in the pass-band of this filter if X
1
at that frequency satisfies
condition as in the case of band-pass filter. X
1
starts at zero for
ω
0 (due to inductor), goes
to ∞ as
ω
→
ω
o
from left, starts at –∞ on the right of
ω
o
and ends up at zero as
ω
→ ∞.
Therefore, 0 < f < f
1
and f
2
< f must be the pass-band of the filter, where f
1
and f
2
are solutions
of the equation . Solving this equation, we get,
[0, f
1
) and (f
2
,∞,) are the pass-bands and (f
1
, f
2
) is the stop-band. It can be shown that
in the case of a band-stop filter also.
The design specifications will be the values of load resistance R
L
, f
1
and f
2
. The design
equations can be derived using the ...