Electric Circuits and Networks, Ist Edition by Pearson

(12.1-19)

Solving this system of equations, we get, A

1

 0.1939, A

2

 –0.4356 and

A

3

 0.2417. Therefore,

is the impulse response of the

second node voltage.

The values of A

1

, A

2

and A

3

for v

3

(t) will be decided by a similar system of

equations shown below:

(12.1-20)

Solving this system of equations, we get, A

1

 0.0.2417, A

2

 0.1938 and

A

3

 –0.4356. Therefore,

is the impulse response of the

third node voltage.

(iv) The circuit conditions at t  0

+

immediately after the application of a unit

step voltage to the initially relaxed circuit is shown in Fig. 12.1-3.

vt

tt t

3

eee V() . . .

...

=+−

−−−

0 2417 0 1938 0 4356

0 1981 3 47 1 555

111 0

0

1

123

1

2

2

2

3

2

1

2

3

sss

sss