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Electric Circuits and Networks, Ist Edition by Pearson
book

Electric Circuits and Networks, Ist Edition by Pearson

by K. S. Suresh Kumar
May 2024
Intermediate to advanced content levelIntermediate to advanced
840 pages
45h 20m
English
Pearson India
Content preview from Electric Circuits and Networks, Ist Edition by Pearson
(12.1-19)
Solving this system of equations, we get, A
1
0.1939, A
2
–0.4356 and
A
3
0.2417. Therefore,
is the impulse response of the
second node voltage.
The values of A
1
, A
2
and A
3
for v
3
(t) will be decided by a similar system of
equations shown below:
(12.1-20)
Solving this system of equations, we get, A
1
0.0.2417, A
2
0.1938 and
A
3
–0.4356. Therefore,
is the impulse response of the
third node voltage.
(iv) The circuit conditions at t 0
+
immediately after the application of a unit
step voltage to the initially relaxed circuit is shown in Fig. 12.1-3.
vt
tt t
3
eee V() . . .
...
=+−
−−−
0 2417 0 1938 0 4356
0 1981 3 47 1 555
111 0
0
1
123
1
2
2
2
3
2
1
2
3
sss
sss
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Publisher Resources

ISBN: 9781299447028