The current in an inductor is related to the voltage across it through the relation
This shows that, with a voltage of 1 V at t 0
+
across it, the current in the inductor
cannot remain at its current value of zero forever. The current has to grow since its derivative
is positive, and hence, it starts growing at the rate of 1/LA/s initially. This in turn implies
that the slope of current versus time curve at t 0
+
will be 1/LA/s.
However, as the current in the inductor grows under the compulsion of the voltage
appearing across it, the resistor starts absorbing voltage. This results in a decrease in the induc-
tor voltage since v
R
and v
L
will add up ...
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