Only an impulse voltage can change the inductor current over [0
–
, 0
+
]. The current at
t 0
+
is read from the given i
L
waveform as 2 A. Therefore, the initial current in 2 H
inductor at t 0
–
2 A.
We use v(t) L(di/dt) to work out the v(t) waveform. i(t) is a piecewise linear
function. The slope of current is 1 A/s in the (0 s, 2 s) interval, 0 A/s in (2 s, 4 s) interval
and –1 A/s in the (4 s, 8 s) interval. Note that all intervals are open intervals. This is so
because the current waveform is not differentiable at the end points of the intervals
and hence the endpoints will have to be excluded from the domain of the derivative ...
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