
Filters and attenuators 325
Example 17 Given that R
x
and R
2
in Figure 18.16 are 450 and
600 ft respectively, and that the attenuation N is 10, calculate the
values of R
A
, R
B
and R
c
-
10
99
R
A
= ^450 x - 2V^450 x 600 ^ x
= 459.09 - 104.97 = 354.12 ft
R
B
= 104.97 H
R
c
= (600 x — | - 104.97 = 507.15 ft
V 99/
10 PRINT "PROG 282"
20 PRINT "ASYMMETRICAL T ATTENUATOR"
30 INPUT "ENTER Rl" ; Rl
40 INPUT "ENTER H2" ; R2
50 INPUT "ENTER ATTENUATION" ; N
60 LET X=Rl*((N*2+l)/(N*2-l))
70 LET
Y =
2*SQR(R1*R2)*(N/(N*2-1 ))
80 LET Z=R2*((N
A
2+1)/(N*2-1))
90 LET RA=X-Y
100 LET RB=Y
110 LET RC=Z-Y
120 PRINT "RA = " RA "OHMS
130 PRINT "RB = " RB "OHMS"
140 PRIN