30 ft respectively, calculate the characteristic impedance.
Ro =
20 x 30
2
20 + (2 x 30)
15 ft
10
PRINT "PROG 2 8 3"
20
PRINT "SYMMETRICAL PI ATTENUATOR"
30
INPUT "ENTER Rl" : Rl
4
0 INPUT "ENTER R2" ; R2
50
LET R0=SQR((R1*(R2
A
2))/(R1+(2*R2)))
60
LET N=(RO+R2)/(R2-RO)
70
PRINT "CHARACTERISTIC IMPEDANCE = " RO
80
PRINT "ATTENUATION = " N
Example 19 Find the attenuation in the network in Example 18.
(N + 1\
(N + 1)
30 = 15 -
(N-\)
30(N - 1) = \5(N + 1)
30/V - 30 =
157V
+ 15
30N - 15N =15 + 30
15N = 45
N = 3 (9.5 dB)
(See program 283, above.) ...
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