Example 16 The mutual inductance between two coils is 0.5 H.
Calculate the average voltage induced in one coil when the current
in the other coil is increased from 1 A to 10 A in 150 mS.
d/ = 10 - 1 = 9 A
0.5 x 9 0.5 x 9 x 10
3
e = = = 30 V
150 x 10"
3
150
10 PRINT "PROG HO"
20 PRINT "INDUCED E.M.F"
30 INPUT "ENTER MUTUAL INDUCTANCE IN HENRYS" ; L
40 INPUT "ENTER INITIAL CURRENT IN AMPS" ; II
50 INPUT "ENTER FINAL CURRENT IN AMPS" ; 12
60 INPUT "ENTER TIME IN MILLISECONDS" ; MS
70 LET 1=12-11
80 LET E=L*I*(10*3/MS ...
Become an O’Reilly member and get unlimited access to this title plus top books and audiobooks from O’Reilly and nearly 200 top publishers, thousands of courses curated by job role, 150+ live events each month, and much more.