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Newnes Circuit Calculations Pocket Book
book

Newnes Circuit Calculations Pocket Book

by Thomas J. Davies
April 2016
Intermediate to advanced content levelIntermediate to advanced
384 pages
12h 56m
English
Newnes
Content preview from Newnes Circuit Calculations Pocket Book
182
Circuit calculations pocket book
Example 11 A 150 ft resistor in series with an inductor takes a
current of 2.5 A from a 500 V supply at a frequency of 50 Hz. Find
the inductance of the coil. The circuit is shown in Figure 11.12.
150 n ,
2.5 A
_500V .
50 Hz
Figure
11.12
True power
Reactive power
Apparent power
V 500
Z = - = = 200 ft
/ 2.5
Z
2
= R
2
+ X\
X
2
L
= Z
2
- R
2
X\ = (200)
2
- (150)
2
X
L
= V[(200)
2
- (150)
2
] = 132.3 ft
132.3 = 2 x TT x 50 x L
132.3
L
= = 0.42 H = 420 mH
2 x TT x 50
V
R
= 2.5 x 150 = 375 V
VL = 2.5 x 132.3 = 330.75 V
= 937.5 W (V
R
f)
= 826.88 VA (V
L
l)
= 1250 VA (VI)
f
K
_
_VR _
375
V
500
R 150
or
=
Z 200
VRI
937. ...
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Publisher Resources

ISBN: 9781483101132