May 2024
Intermediate to advanced
665 pages
23h 2m
English
book
The X86 Microprocessors: Architecture and Programming (8086 to Pentium), 1st Edition
by Lyla B. Das
Content preview from The X86 Microprocessors: Architecture and Programming (8086 to Pentium), 1st Edition
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THE INTERRUPT STRUCTURE OF 8086 253
Example 8.1
Find the address (in the IVT) of the interrupt vector of INT 61H. Find the physical address of
the ISR corresponding to this interrupt if the vector is 0F00:9872.
Solution
e type number of the interrupt is 61H = 97 in decimal.
e address of the interrupt vector is 97 × 4 = 388 = 184H.
us, the interrupt vector is to be stored in the IVT in location 0000:0184 onwards.
For the ISR, the CS value is 0F00H and the IP value is 9872H. e part of the interrupt vector
table which has these vectors stored is shown.
Address
72H
0FH
00
98H
0184H
0186H
Now, How Does the Interrupt Vector Table Get These Entries? ...
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