December 2012
Beginner
528 pages
17h 31m
English
Content preview from Introduction to Electrical Power and Power Electronics
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488 Appendix
These two indications lead us to the sequence network shown in Figure A.3. For
this circuit, therefore, the total driving voltage divided by the total impedance gives
the current. The total driving voltage is the sum of three sequence voltages (i.e.,
VVV
120
++
), and the total impedance is
ZZZZ
ZZ
120
333
+++++
()
fgn
.
Therefore,
IIIVVV ZZZ
120120 12
===++
()
÷++
00
333+++
()
ZZZ
fgn
.
(A.10)
L-G fault
N
I
a
Line B
Line C
V
c
Line A
V
a
I
a
V
b
Ground current loop
Z
f
Z
n
V
a
= 0
Z
g
FIGURE A.2 Single-line to ground fault in three-phase power system.
⅓ I
a
V
1
Z
1
Positive
sequence
network
V
2
Z
2
Negative
sequence
network
V
0
Z
0
Zero
sequence
network
V
a
3 Z
f
3 Z
n
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