
49Common Aspects of Power Equipment
IR IX IX IR
sL
OA AB
222
2
=+=+×+×
+× −×cossin (cos sθθ θ iin )θ
.
(2.14)
For typical pf around 0.85, we can approximately write the source voltage V
s
=
OB= OA and, subsequently, the voltage drop magnitude:
V
drop
= V
s
– V
L
= OA – V
L
= I × R cos θ + I × X sin θ = I × (R cos θ + X sin θ). (2.15)
We can take the following as the effective impedance between the source and the
load:
Z
eff
= R cos θ + X sin θ (2.16)
which, when multiplied with current I, gives the voltage drop by simply applying
Ohm’s law:
V
drop
= I × Z
eff
. (2.17)
All calculations are done using volts, amperes, and ohms per phase and taking θ
positi ...