You want to create an RGB value
to use with `setRGB( )`

based on the red, green, and blue part values.

Use the bitshift left and
bitwise
`OR`

operators.

The easiest way to combine individual red, green, and blue components
into a single RGB value is to use bitwise operations. Simply shift
the red value left by 16 bits and the green value left by 8 bits,
then combine them with the blue value using the bitwise
`OR`

operator, as follows:

red = 100; green = 100; blue = 100; rgb = (red << 16) | (green << 8) | (blue); // Create theobject. my_color = new Color(myMovieClip); // Set the RGB color. my_color.setRGB(rgb);`Color`

The bitshift left operator (`<<`

) effectively
multiplies a number by two for each bit position that the number is
shifted (this is similar to how shifting a decimal number one decimal
place to the left effectively multiplies it by 10). In this context,
the bitwise `OR`

operator (`|`

)
essentially concatenates the shifted numbers together. Therefore,
assuming that `red`

, `green`

, and
`blue`

are each in the range of 0 to 255, the
following:

rgb = (red << 16) | (green << 8) | (blue);

is equivalent to:

rgb = (red * Math.pow(2,16)) + (green * Math.pow(2,8)) + blue;

or:

rgb = (red * 65536) + (green * 256) + blue;

In practice, it is often easier
to use ```
Color.setTransform(
)—
```

in which the red, green, and blue components are
specified as separate properties of a transform object—to alter
the targeted clip’s color. Furthermore,
`setTransform( )`

allows ...

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