May 2024
Intermediate to advanced
889 pages
30h 8m
English
book
The X 86 Microprocessors: Architecture, Programming and Interfacing (8086 to Pentium) 2nd Edition by Pearson
by Lyla B. Das
Content preview from The X 86 Microprocessors: Architecture, Programming and Interfacing (8086 to Pentium) 2nd Edition by Pearson
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THE INTERRUPT STRUCTURE OF 8086 8-5
Example 8.1
Find the address (in the IVT) of the interrupt vector of INT 61H. Find the physical
address of the ISR corresponding to this interrupt if the vector is 0F00:9872.
Solution
The type number of the interrupt is 61H = 97 in decimal.
The address of the interrupt vector is 97 × 4 = 388 = 184H.
Thus, the interrupt vector is to be stored in the IVT in location 0000:0184 onwards.
For the ISR, the CS value is 0F00H and the IP value is 9872H. The part of the interrupt
vector table which has these vectors stored is shown.
Address
72H
0FH
00
98H
0184H
0186H
Now, How Does the Interrupt Vector Table Get These Entries?
It was ...
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