8086 has a 16-bit memory bus – which means that data transfer can occur at a maximum
rate of 16 bits (one word) per bus cycle. However, sometimes, only a byte needs to be
accessed. This means that the processor must have both options – i.e., both byte and
word transfer must be possible. We know that for a word transfer two byte locations must
be accessed; i.e., two addresses are actually needed.
Keeping these concepts in mind, let us see how memory is organized for 8086. A
16-bit data can be obtained by accessing two memory chips in parallel, each having
8 bits each of the word (see Fig. 7.11). ...
Become an O’Reilly member and get unlimited access to this title plus top books and audiobooks from O’Reilly and nearly 200 top publishers, thousands of courses curated by job role, 150+ live events each month, and much more.
O’Reilly covers everything we've got, with content to help us build a world-class technology community, upgrade the capabilities and competencies of our teams, and improve overall team performance as well as their engagement.
Julian F.
Head of Cybersecurity
I wanted to learn C and C++, but it didn't click for me until I picked up an O'Reilly book. When I went on the O’Reilly platform, I was astonished to find all the books there, plus live events and sandboxes so you could play around with the technology.
Addison B.
Field Engineer
I’ve been on the O’Reilly platform for more than eight years. I use a couple of learning platforms, but I'm on O'Reilly more than anybody else. When you're there, you start learning. I'm never disappointed.
Amir M.
Data Platform Tech Lead
I'm always learning. So when I got on to O'Reilly, I was like a kid in a candy store. There are playlists. There are answers. There's on-demand training. It's worth its weight in gold, in terms of what it allows me to do.