1. Let the probability that the household has computers with Internet access or two or more
computers be P(E
1
or E
2
). From the additional rule of probability
121212
(or)()()(and)PEEPEPEPEE=+−
After placing the values,
12
(or)0.60.70.50.8PEE=+−=
Therefore, the probability that a household has computers with Internet access or two or more
computers is 0.8.
2. Probability that the household has computers with Internet access or two or more computer sets
but not both.
P(Probability that the household has computers with Internet access or two or more compute
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