Solution From the question = 1.10 per hour and in an exponential distribution, prob-
abilities can be computed by the formula P(xx
0
) =
0
−λx
e
. The value of can
be obtained as
11
0.9090
1.10
===
.
(a) = 0.9090 indicates that on an average, 0.9090 hours will elapse between
arrivals.
(b) The probability that at least 5 hours will elapse between arrivals can be com-
puted as
Prob(x 5/ = 1.10) =
0
−λx
e
= e
–1.10(5)
=0.0040
(c) The probability that at least 3 hours will elapse between train arrivals is
Prob(x 3/ = 1.10) =
0
−λx
e
= e
–1.10(3)
= 0.0368
Figure 7.47 is the Minitab output exhibiting computation of cumulative ...
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