For rows the calculated value of F is 0.65. This value is less than the tabular
value (2.15) and falls in the acceptance region. Hence, null hypothesis is accepted
and the alternative hypothesis is rejected.
There is enough evidence to believe that there is a signicant difference in
terms of mean scores for ve different products. There is no signicant difference
in terms of scores obtained by 10 different customers. The result that we have ob-
tained may be due to chance. So, the management should concentrate on ensuring
customers loyalty for different products.
Example 12.8A companypurchased four machines and
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