December 2005
Intermediate to advanced
475 pages
12h 6m
English
In homogeneous case, the term u(t) is not present.
The Eq. (9.49) becomes
Taking Laplace transform of Eq. (9.55), we get,
∴ (sI – A) X(s) = x(0)
∴ X (s) = (sI – A)−1x(0) (9.56)
∴ X(s) = ϕ(s) x (0) (9.57)
where ϕ(s) = (sI – A) −1 (9.58)
called the resolvent matrix.
Taking inverse Laplace transform of Eq. (9.59), it can be written as
where ϕ(t) is given in Eq. (9.60) ...
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