August 2017
Intermediate to advanced
360 pages
8h 35m
Chinese
Content preview from 算法技术手册（原书第2 版）
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222
｜
第
8
章
//
从原始的边集中取出边进行处理，忽略连接添加的“源顶点”和“汇点”的边。
//
当且仅当流等于
1
时，这条边属于解的一部分。
ArrayList<Pair> pairs = new ArrayList<Pair>();
for (EdgeInfo ei : edges) {
if (ei.start != srcIndex && ei.end != tgtIndex) {
if (ei.getFlow() == 1) {
pairs.add(new Pair(reverse.get(ei.start),
reverse.get(ei.end)));
}
}
}
return pairs.iterator(); //
使用迭代器生成
解决方案。
}
}
8.3.3 算法分析
想要更高效地规约问题，就必须将问题实例和计算方案进行高效映射。
二分图问题
M
=
（
S
,
T
,
P
）
可以在
n
+
m
+
k
步内转换成为一个图
G
= (
V
,
E
)
。转换后的图
G
拥有（
n
+
m
+ 2
）
个顶点以及（
n
+
m
+
k
）条边，因此图
G
的规模只比原始二分图问题的规模大一个常数。
这个重要特性保证我们能够高效地求解二分图问题。在
Ford-Fulkerson
算法计算出最大
流之后，网络中流量为
1
的边就对应了二分图中选择的匹配。要“读取”二分图问题的
解决方案，就需要从流网络中读取边，而读取这些边需要 ...
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I wanted to learn C and C++, but it didn't click for me until I picked up an O'Reilly book. When I went on the O’Reilly platform, I was astonished to find all the books there, plus live events and sandboxes so you could play around with the technology.Addison B.
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I'm always learning. So when I got on to O'Reilly, I was like a kid in a candy store. There are playlists. There are answers. There's on-demand training. It's worth its weight in gold, in terms of what it allows me to do.