August 2017
Intermediate to advanced
360 pages
8h 35m
Chinese
Content preview from 算法技术手册（原书第2 版）
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296
｜
第
10
章
if n is a leaf then
❺
return entry if n contains t otherwise False
else
foreach child c of n do
❻
if c contains t then
return search(c, t)
❼
end
range (n, t)
if target wholly contains n's bounding box then
❽
return all descendant rectangles
else if n is a leaf
return all entries that intersect t
else
result = null
foreach child c of n do
❾
if c overlaps t then
result = union of result and range(c, t)
return result
❶
如果仍有空间，将条目加入叶结点中。
❷
否则，将
M
+ 1
个条目在旧的叶结点和新的结点之间分配。
❸
可能需要调整条目到根结点的路径。
❹
R
树的高度可能会在添加完后有所增加。
❺
叶结点包含实际的条目。
❻
递归搜索
每个子结点
，因为区域有可能重合。
❼
一旦发现条目，将其返回。
❽
检查隶属关系的高效操作。
❾
有可能需要执行多次递归查询。
10.8.1 ...
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I wanted to learn C and C++, but it didn't click for me until I picked up an O'Reilly book. When I went on the O’Reilly platform, I was astonished to find all the books there, plus live events and sandboxes so you could play around with the technology.Addison B.
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I'm always learning. So when I got on to O'Reilly, I was like a kid in a candy store. There are playlists. There are answers. There's on-demand training. It's worth its weight in gold, in terms of what it allows me to do.