August 2017
Intermediate to advanced
360 pages
8h 35m
Chinese
Content preview from 算法技术手册（原书第2 版）
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78
｜
第
4
章
/**
插入每个元素并且增加计数
*/
ENTRY *e = (ENTRY *) calloc (1, sizeof (ENTRY));
e->element = ar[i];
if (buckets[k].head == NULL) {
buckets[k].head = e;
} else {
e->next = buckets[k].head;
buckets[k].head = e;
}
buckets[k].size++;
}
/*
排序、读出并且覆盖
ar */
extract (buckets, cmp, ar, n);
free (buckets);
}
例
4-8
给出了对于从
[0, 1)
中均匀选择的数字的桶排序，其中包含了
hash
和
numBuckets
函数实现示例。
例
4-8
：处理
[0, 1)
范围内的元素时使用的
hash
和
numBuckets
函数
static int num;
/**
使用的桶数量和元素数量
相等
*/
int numBuckets(int numElements) {
num = numElements;
return numElements;
}
/**
*
散列函数将元素映射到桶中。因为散列函数值的范围是
[0, 1)
，
*
所以将每个桶的大小分为
1/num
*/
int hash(double *d) {
int bucket ...
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