*1. Find the resistivity of an intrinsic semiconductor with intrinsic concentration of 2.5 × 10 ^{19}* per m

**Sol:** Given data are:

Intrinsic concentration (*n*_{i}) = 2.5 × 10^{19}/m^{3}

Mobility of electrons (*μ*_{n}) = 0.40 m^{2}/V-s

The mobility of holes (*μ*_{p}) = 0.20 m^{2}/V-s

The conductivity of an intrinsic semiconductor (σ_{i}) = *n*_{i}*e*[*μ*_{n} + *μ*_{p}]

*2. Calculate the number of donor atoms per* m^{3} *of n-type material having resistivity of 0.25* Ω-m, *the mobility of electrons is 0.3* m^{2}/V-s.

**Sol:** We know:

[Since *n* = number of free electron per m^{3} ≈ number of donor atoms in n-type]

*3. At ...*

Start Free Trial

No credit card required