Now, suppose there are hundred apples. It again becomes difficult to represent by one 1
continuing hundred times from rightmost to leftmost place. However, if we use the assump-
tion that the weight of the left side digit is always ten times compared to the one on the right
side of it, which means we assume that base = 10, then 100 represents the hundred apples.
We get the similar formula as above. Here p = 2, 1 and 0, at leftmost, middle and right most
places, respectively.
Total number,100= 1 ´
w
d
p
+ 0 ´
w
d
p
+
0 ´
w
d
p
...(2.2)
where w
d
= 10.
If you put by mistake an addition 0 on the right, the number of apples will become ten
times ...
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