TABLE 18.14State Table for Figure 18.3(b) asynchronous sequential circuit operating in funda-
mental mode
PresentExcitation variables before thePresent output
statetransition (O
G0
, O
G1
, O
G2
) ;
0
(x
q1
, x
q2
)Input X = 0Input X = 1Input X = 0Input X = 1
0, 0 S
0
S
2
S
0
00
0, 1 S
1
S
2
S
0
10
1, 0 S
2
S
3
S
1
11
1, 1 S
3
S
3
S
0
11
Example 18.4
Why is the flow table is not possible for a circuit with state table as Table 18.14?
Solution
This is because all entries are unstable due to JK FF. In flow table, at least one stable state
must be there in a row. State table shows that Y is changing in both the cases. When X input
is 1, S
2
®S
1
, S
1
®S
0
, S
2
is unstable. ...
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