This is a problem of comparison of means with independent samples. Go to Stat > Basic Statistics > 2-Sample t
Choose ‘greater than’ as alternative hypothesis. That is, either the fat content is the same in both varieties, or – if the null hypothesis is rejected – the usual variety contains more fat. The result is:
The p-value obtained is 0.045. Therefore, with a significance level of 5% it can be said that the new variety has less fat than the usual variety.