August 2020
Beginner to intermediate
332 pages
8h 16m
Japanese
book
動かして学ぶ量子コンピュータプログラミング ―シミュレータとサンプルコードで理解する基本アルゴリズム
by Eric R. Johnston, Nic Harrigan, Mercedes Gimeno-Segovia, 北野 章, 丸山 耕司
Content preview from 動かして学ぶ量子コンピュータプログラミング ―シミュレータとサンプルコードで理解する基本アルゴリズム
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148
7
章
QFT
：量子フーリエ変換
おそらく、図7-26 の例のほうがわかりやすいでしょう。図 7-26では、入力値が
2
である
4
キュビット
レジスタがあるので、狙った出力状態を得ることを目的として、連続した値
1
つずつを
360
°
×
n/2
N
＝
360
°
×
2/2
4
＝
45
°
度ずつ回転します。結果を図 7-28に示します。
図7-28
°
この単純なルールに従って回転すると、レジスタの相対位相で必要な周期性を正確に得ることがで
き ま す（ も ち ろ ん 、
360
°
≡
0
°
、
405
°
≡
45
°
と な り ま す ）。
7.6.2
演算ごとに調べる
図7-25 の
invQFT
回路は、条件付き回転のルールを実装するための巧妙かつコンパクトな方法です。
これを確認するために、図7-25 で実行する必要があるタスクを
2
つの個別の要件に分割するとよいで
しょう。
1.
θ
= n/2
N
×
360
°
の値を決定する（
n
はレジスタに最初に格納された値）。
2.
ステップ
1
で決定した角度
θ
の倍数でレジスタ内の各円の位相を回転する（倍数は、円の
10
進法
の 値 ）。
invQFT
は、ステップ
1
、ステップ
2
を一度に実行します。しかし、その動作をより明確に確認する
ために、個々のステップがどのように実行されるかを別々に説明しましょう。逆に思えるかもしれませ
んが、実際にはステップ
2
から始めるのが最もわかりやすいでしょう。レジスタの各値の回転角度がそ
の値の倍数である場合、
PHASE
をどのよう ...
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I'm always learning. So when I got on to O'Reilly, I was like a kid in a candy store. There are playlists. There are answers. There's on-demand training. It's worth its weight in gold, in terms of what it allows me to do.