August 2020
Beginner to intermediate
332 pages
8h 16m
Japanese
book
動かして学ぶ量子コンピュータプログラミング ―シミュレータとサンプルコードで理解する基本アルゴリズム
by Eric R. Johnston, Nic Harrigan, Mercedes Gimeno-Segovia, 北野 章, 丸山 耕司
Content preview from 動かして学ぶ量子コンピュータプログラミング ―シミュレータとサンプルコードで理解する基本アルゴリズム
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8.4
位相推定の使い方
159
位相推定
図8-4
入力レジスタの状態は
phase_est()
を適用する前と後で変わりません。これは期待通りです。では、
出力レジスタの値はいくつでしょうか？
180
°
という結果を期待していましたが、結果は
8
でした。
8.4.2
出力
出力レジスタを構成する
m
キュビットに
READ
演算を適用することで、固有位相を取得します。位相
推定の内部動作によって、
θ
j
が
360
°
を分母とする分数になることに注意してください。この値は、固
有位相の大きさに相当する分数として、出力レジスタにおいてエンコードされます。言い換えると、出
力の固有位相が
90
°
の場合、これは一回転の
1/4
に相当しますが、このとき
3
キュビットの出力レジス
タが
2
に対するバイナリ値を生成するものと期待されます。これは、レジスタがとりうる
2
3
＝
8
個の値
の
1/4
となります。図8-4 の場合、
180
°
の位相を期待していました。
180
°
は一回転の
1/2
に相当します。
2
4
＝
16
個の値をとる
4
キュビットの出力レジスタの場合、
8
という値が期待されます。
8
がレジスタの
サイズのちょうど半分だからです。式8-1に示す単純な数式で、固有位相（
θ
j
）と読み出すレジスタの値
（
R
）をレジスタのサイズの関数として表すことができます。
式 8-1
R
θ
j
m
R
=
θ
j
×
2
m
360
°
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O’Reilly covers everything we've got, with content to help us build a world-class technology community, upgrade the capabilities and competencies of our teams, and improve overall team performance as well as their engagement.Julian F.
I wanted to learn C and C++, but it didn't click for me until I picked up an O'Reilly book. When I went on the O’Reilly platform, I was astonished to find all the books there, plus live events and sandboxes so you could play around with the technology.Addison B.
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I'm always learning. So when I got on to O'Reilly, I was like a kid in a candy store. There are playlists. There are answers. There's on-demand training. It's worth its weight in gold, in terms of what it allows me to do.