One cycle of variation covers a distance of one wavelength (λ) on the tape. If *T* is the time period in seconds then

Distance covered = λ/*T* (speed)

If S denotes the speed of the tape, we have

For *optimum output*, the gap-width should be half a wavelength of the maximum usable frequency (*f _{m}*)

Equation 10.2 gives the maximum usable frequency (*f _{m}*) in terms of tape speed

**Example 10.1 ...**

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