years[["Johnson"]] <- NULL # Remove the element labeled "Johnson"
years
#> $Kennedy
#> [1] 1960
#>
#> $Carter
#> [1] 1976
#>
#> $Clinton
#> [1] 1994
也可以通过这种方式删除多个元素:
years[c("Carter", "Clinton")] <- NULL # Remove two elements
years
#> $Kennedy
#> [1] 1960
5.11 将列表转换为向量
5.11.1 问题
需要将列表中的所有元素“展平”赋值给一个向量。
5.11.2 解决方案
使用unlist函数。
5.11.3 讨论
许多情况下需要向量。例如,R中的基本统计函数适用于向量,但不适用于列表。如果
iq.scores是一个包含数值的列表,那么我们不能直接计算它们的平均值:
iq.scores <- list(100, 120, 103, 80, 99)
mean(iq.scores)
#> Warning in mean.default(iq.scores): argument is not numeric or logical:
#> returning NA
#> [1] NA
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