September 2010
Intermediate to advanced
310 pages
12h 1m
German
Content preview from Handlungstheoretische Semantik
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Beweise D15
Für (i): Aus GG
1
(P,A) bei aP G(a,A), nach G2 also G(a, A). Ange-
nommen, GG
1
(P, A), so auch G(a, A) – im Widerspruch zu G(a,
A). Also bei GG
1
(P,A) auch GG
1
(P, A).
Für (ii): Aus GG
n+1
(P,A) nach D18.b GG
1
(P,GG
n
(P,A)), nach I.V. und
mit T.G5-1 also auch GG
1
(P,GG
n
(P,A)); bei aP also auch G(a,
GG
n
(P,A)). Angenommen: GG
n+1
(P,A), so nach D18.b auch
GG
1
(P,GG
n
(P,A)), für aP also auch G(a,GG
n
(P,A)) – im Wider-
spruch zu G(a,GG
n
(P,A)) – welches mit G2 aus G(a,GG
n
(P,A)).
Also bei GG
n+1
(P,A) auch GG
n+1
(P,A).
(T.G5-1 lässt sich bereits allein mit den G-Prinzipien T.G0-1 und T.G1-1
beweisen.)
Für T.G2*: GW(P,A) GW(P,A)
Aus GW(P,A) nach L.G1 GG(P,A), und daraus mit T.G2 GG(P,A),
wegen ...
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I'm always learning. So when I got on to O'Reilly, I was like a kid in a candy store. There are playlists. There are answers. There's on-demand training. It's worth its weight in gold, in terms of what it allows me to do.